[2022] Pass 1z1-071 Exam - Real Questions and Answers
1z1-071 Exam Questions Get Updated [2022] with Correct Answers
Difficulty in writing the ORACLE 1Z0-071 Certification Exam
There are many difficulties in writing the ORACLE 1Z0-071 Certification Exam. First of all, it is difficult to find enough time to study for the exam. Next, there is the issue of paying attention and finding enough information on how to study for this exam. And lastly, it can be even harder to come up with a cluster of practice problems or questions that provide adequate preparation for this exam.
Difficulty in writing the ORACLE 1Z0-071 Certification Exam is not an exception. Many candidates are faced with this difficulty at the beginning of their preparation for this exam. You need to know that you cannot pass the ORACLE 1Z0-071 Certification Exam without attempting it at least once. Therefore, if you are stuck with any problem during your preparation, then you should try to identify and sorting of the problem and try again. It has been observed that many people have a hard time writing a test because they do not have a sufficient amount of knowledge regarding the subject being examined by the test, and they left most of the questions unanswered. It is also important to know that you should take a test and try as many times as possible to get the best result. So what should we do, then? I would like to suggest that you should take advantage of the ActualTestsQuiz.
The ORACLE 1Z0-071 Certification Exam is a significant first step towards your career in IT administrator oracle 1Z0-071 Certification Exam certifies that you have the skills required to enter the occupation of SQL Developer. It is this certification that validates that you have the required knowledge, skills, and abilities to work as a SQL Developer. The certification exam tests your IT knowledge, so there are no worries about being out of date with the latest technology. So long as you keep up with current technology news or subscribe to technologically oriented blogs, and prepare yourself by downloading a PDF of the Oracle 1Z0-071 Dumps, there is no way you can fail ORACLE 1Z0-071 Certification Exam. Know the exam's structure and the level of difficulty:
Prerequisites
There are no official requirements for passing the Oracle 1Z0-071 exam. However, it is recommended that the students have a good grasp of SQL syntax rules. They also need to be able to use general SQL functions, identify the result of fundamental DDL operations, and know how to implement SQL statements and functions.
NEW QUESTION 108
View the exhibit and examine the data in ORDERS_MASTERand MONTHLY_ORDERStables.
ORDERS_MASTER
ORDER_TOTAL
ORDER_ID
1 1000
2 2000
3 3000
4
MONTHLY_ORDERS
ORDER_TOTAL
ORDER_ID
2 2500
3
Evaluate the following MERGEstatement:
MERGE_INTO orders_master o
USING monthly_orders m
ON (o.order_id = m.order_id)
WHEN MATCHED THEN
UPDATE SET o.order_total = m.order_total
DELETE WHERE (m.order_total IS NULL)
WHEN NOT MATCHED THEN
INSERT VALUES (m.order_id, m.order_total)
What would be the outcome of the above statement?
- A. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2 and 3.
- B. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2, 3 and 4.
- C. The ORDERS_MASTERtable would contain the ORDER_IDs1 and 2.
- D. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2 and 4.
Answer: D
Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_9016.htm
NEW QUESTION 109
Evaluate the following statement.
INSERT ALL
WHEN order_total < 10000 THEN
INTO small_orders
WHEN order_total > 10000 AND order_total < 20000 THEN
INTO medium_orders
WHEN order_total > 200000 AND order_total < 20000 THEN
INTO large_orders
SELECT order_id, order_total, customer_id
FROM orders;
Which statement is true regarding the evaluation of rows returned by the subquery in the INSERT statement?
- A. They are evaluated by the first WHENclause. If the condition is false, then the row would be evaluated by the subsequent WHENclauses.
- B. The insert statement would give an error because the ELSEclause is not present for support in case none of WHENclauses are true.
- C. They are evaluated by the first WHENclause. If the condition is true, then the row would be evaluated by the subsequent WHENclauses.
- D. They are evaluated by all the three WHENclauses regardless of the results of the evaluation of any other WHENclause.
Answer: D
Explanation:
Explanation/Reference:
References:
http://psoug.org/definition/WHEN.htm
NEW QUESTION 110
Which two statements are true about Oracle databases and SQL?
- A. A query can access only tables within the same schema.
- B. When you execute an UPDATE statement, the database instance locks each updated row.
- C. A user can be the owner of multiple schemas In the same database.
- D. Updates performed by a database user can be rolled back by another user by using the ROLLBACK command.
- E. The database guarantees read consistency at select level on user-created tablers.
Answer: B,E
NEW QUESTION 111
Examine the structure of the SALES table. (Choose two.)
Examine this statement:
Which two statements are true about the SALES1 table? (Choose two.)
- A. It will have NOT NULL constraints on the selected columns which had those constraints in the SALES table.
- B. It will not be created because the column-specified names in the SELECT and CREATE TABLE clauses do not match.
- C. It will not be created because of the invalid WHERE clause.
- D. It has PRIMARY KEY and UNIQUE constraints on the selected columns which had those constraints in the SALES table.
- E. It is created with no rows.
Answer: A,E
NEW QUESTION 112
View the Exhibit and examine the structure of the ORDERS table.
You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?
- A. SELECT order_id, order_date FROM ordersWHERE order_date > IN(SELECT order_date FROM orders WHERE customer_id = 101);
- B. SELECT order_id, order_date FROM ordersWHERE order_date >ANY(SELECT order_date FROM orders WHERE customer_id = 101);
- C. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;
- D. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT order_date FROM orders WHERE customer_id = 101);
Answer: D
NEW QUESTION 113
View the exhibit and examine the structure of ORDERS and CUSTOMERS tables.
Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.
- A. INSERT INTO orders (order_id, order_date, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), order_total)VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
- B. INSERT INTO(SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_totalFROM orders o, customers cWHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND c.credit_limit=600)VALUES (1,'10-mar-2007', 'direct', (SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
- C. INSERT INTO ordersVALUES (1,'10-mar-2007', 'direct',(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
- D. INSERT INTO orders (order_id, order_date, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), order_total)VALUES (1,'10-mar-2007', 'direct', &&customer_id, 1000);
Answer: C
NEW QUESTION 114
View the exhibit and examine the description of SALES and PROMOTIONS tables.
You want to delete rows from the SALES table, where the PROMO_NAME column in the PROMOTIONS table has either blowout sale or everyday low price as values.
Which three DELETE statements are valid? (Choose three.)
- A. DELETEFROM salesWHERE promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'blowout sale')OR promo_name = 'everyday low price');
- B. DELETEFROM salesWHERE promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'blowout sale')OR promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'everyday low price')
- C. DELETEFROM salesWHERE promo_id IN (SELECT promo_idFROM promotionsWHERE promo_name IN = 'blowout sale','everyday low price'));
- D. DELETEFROM salesWHERE promo_id = (SELECT promo_idFROM promo_name = 'blowout sale')AND promo_id = (SELECT promo_idFROM promotionsWHERE promo_name = 'everyday low price')FROM promotionsWHERE promo_name = 'everyday low price');
Answer: A,B,C
NEW QUESTION 115
Which statement is true regarding the UNION operator?
- A. Names of all columns must be identical across all select statements.
- B. The number of columns selected in all select statements need not be the same.
- C. Null values are not ignored during duplicate checking.
- D. By default, the output is not sorted.
Answer: C
NEW QUESTION 116
Examine these SQL statements which execute successfully:
Which two statements are true after execution? (Choose two.)
- A. The primary key constraint will be enabled and IMMEDIATE.
- B. The foreign key constraint will be disabled.
- C. The foreign key constraint will be enabled and IMMEDIATE.
- D. The primary key constraint will be enabled and DEFERRED.
- E. The foreign key constraint will be enabled and DEFERRED.
Answer: A,B
NEW QUESTION 117
View the Exhibit and examine the structure of the PROMOTIONS table.
Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
- A. It shows COST_REMARK for all the promos in the table.
- B. It shows COST_REMARK for all the promos in the promo category 'TV'.
- C. It produces an error because subqueries cannot be used with the CASE expression.
- D. It produces an error because the subquery gives an error.
Answer: A
NEW QUESTION 118
You want to write a query that prompts for two column names and the WHERE condition each time it is executed in a session but only prompts for the table name the first time it is executed.
The variables used in your query are never undefined in your session?
Which query can be used?
- A. Option E
- B. Option C
- C. Option B
- D. Option A
- E. Option D
Answer: E
NEW QUESTION 119
Examine the description of the BOOKS_TRANSACTIONS table:
Examine this partial SQL statement:
SELECT * FROM books_transactions
Which two WHERE conditions give the same result?
- A. WHERE borrowed_date = SYSDATE AND transaction_type = 'RM' AND member_id = 'A101' OR member_id = 'A102');
- B. WHERE borrowed_date = SYSDATE AND transaction_type = 'RM' OR member_id IN('A101','A102');
- C. WHERE borrowed_date = SYSDATE AND transaction_type = 'RM' AND (member_id = 'A101' OR member_id = 'A102'));
- D. WHERE (borrowed_date = SYSDATE AND transaction_type = 'RM') OR member_id IN ('A101','A102');
- E. WHERE borrowed_date = SYSDATE AND transaction_type = 'RM' OR member_id IN('A101','A102');
Answer: B,D
NEW QUESTION 120
Examine the structure of the EMPLOYEES table:
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the name, joining date, and manager for all employees. Newly hired employees are yet to be assigned a department or a manager. For them, 'No Manager' should be displayed in the MANAGER column.
Which SQL query gets the required output?
- A. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e NATURAL JOIN employees mON (e.manager_id = m.employee_id).
- B. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
- C. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e JOIN employees mON (e.manager_id = m.employee_id);
- D. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e RIGHT OUTER JOIN employees mON (e.manager_id = m.employee_id);
Answer: B
NEW QUESTION 121
View the exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement?
- A. listing of customers who do not have a credit limit and were born before 1980
- B. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
- C. finding the number of customers, in each city, who's marital status is 'married'.
- D. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
- E. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
Answer: B,D
NEW QUESTION 122
Examine the structure of the MEMBERS table:
Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution? (Choose the best answer.)
- A. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
- B. It fails because a column alias cannot be used in the ORDER BY clause.
- C. It displays all cities in ascending order, within which the last names are further sorted in descending order.
- D. It displays all cities in descending order, within which the last names are further sorted in descending order.
Answer: C
NEW QUESTION 123
View the exhibits and examine the structures of the COSTSand PROMOTIONStables.
Evaluate the following SQL statement:
What would be the outcome of the above SQL statement?
- A. It displays prod IDs in the promos with the highest cost in the same time interval.
- B. It displays prod IDs in the promos with the lowest cost in the same time interval.
- C. It displays prod IDs in the promos which cost less than the highest cost in the same time interval.
- D. It displays prod IDs in the promo with the lowest cost.
Answer: C
NEW QUESTION 124
Examine this partial command:
Which two clauses are required for this command to execute successfully?
- A. the DEFAULT DIRECTORY clause
- B. the access driver TYPE clause
- C. the ACCESS PARAMETERS clause
- D. the REJECT LIMIT clause
- E. the LOCATION clause
Answer: B,E
NEW QUESTION 125
Examine these statements executed in a single Oracle session:
Which three statements are true? (Choose three.)
- A. There is no row containing pencil.
- B. The code for fountain penis 3.
- C. There is no row containing pen.
- D. The code for penis 10.
- E. There is no row containing fountain pen.
- F. The code for penis 1.
Answer: A,B,F
NEW QUESTION 126
Which two queries will result in an error?
- A. SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE ANNUAL_SALARY > 100000
ORDER BY ANNUAL_SALARY; - B. SELECT FIRST_NAME,LAST_NAME FROM EMPLOYEES;
- C. SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE ANNUAL_SALARY > 100000
ORDER BY 12 * SALARY ; - D. SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE 12 * SALARY > 100000
ORDER BY 12 * SALARY; - E. SELECT FIRST_NAME LAST_NAME FROM EMPLOYEES;
- F. SELECT LAST_NAME,12 * SALARY AS ANNUAL_SALARY
FROM EMPLOYEES
WHERE 12 * SALARY > 100000
ORDER BY ANNUAL_SALARY;
Answer: A,C
NEW QUESTION 127
Examine the structure of the EMPLOYEEStable.
There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?
SELECT e.last_name, m.manager_id
- A. FROM employees e LEFT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123;
SELECT e.last_name, e.manager_id - B. FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123; - C. FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
SELECT m.last_name, e.manager_id - D. FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123;
SELECT e.last_name, m.manager_id
Answer: B
Explanation:
Explanation
NEW QUESTION 128
The PRODUCT_INFORMATIONtable has a UNIT_PRICEcolumn of data type NUMBER (8, 2).
Evaluate this SQL statement:
SELECT TO_CHAR(unit_price, '$9,999') FROM product_information;
Which two statements are true about the output? (Choose two.)
- A. A row whose UNIT_PRICEcolumn contains the value 10235.99will be displayed as #######.
- B. A row whose UNIT_PRICEcolumn contains the value 1023.99will be displayed as $1,024.
- C. A row whose UNIT_PRICEcolumn contains the value 10235.99will be displayed as $1,023.
- D. A row whose UNIT_PRICEcolumn contains the value 10235.99will be displayed as $1,0236.
- E. A row whose UNIT_PRICEcolumn contains the value 1023.99will be displayed as $1,023.
Answer: A,E
NEW QUESTION 129
Which two tasks can be performed by using Oracle SQL statements? (Choose two.)
- A. querying data from tables in different databases
- B. starting up a database instance
- C. executing operating system (OS) commands in a session
- D. connecting to a database instance
- E. changing the password for an existing database user
Answer: A,E
Explanation:
Explanation
References:
http://www.techonthenet.com/oracle/password.php
https://docs.oracle.com/cd/B28359_01/server.111/b28324/tdpii_distdbs.htm
NEW QUESTION 130
View the exhibit and examine the structure in ORDERSand ORDER_ITEMStables.
You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATEVIEWstatement would create the views successfully?
- A. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date; - B. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date; - C. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date; - D. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id) ||
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date
WHITH CHECK OPTION;
Answer: A
NEW QUESTION 131
......
Practice 1z1-071 Questions With Certification guide Q&A from Training Expert ActualTestsQuiz: https://vceplus.actualtestsquiz.com/1z1-071-test-torrent.html
